Omission of credentials for individual contributors and reviewers.

Credentials should read as follows under Contributors and Reviewers: Mark Kovacs, DVM, and Christa Regan, BS.

Simian Hemorrhagic Fevers (Ebola, Marburg) are listed as Rhabdoviruses.

Simian Hemorrhagic Fevers (Ebola, Marburg) are Filoviruses (in the Filoviridae virus family).

Rabies is listed as a Rabies virus.

Rabies is a Lyssavirus (in the Rhabdoviridae virus family).

Sentence states that: Giardia species are found in dogs, cats, and nonhuman primates.... While this is true, Giardia is not exclusive to dogs, cats, and nonhuman primates.

Sentence should read: Giardia species are found in most mammals and birds; G. lamblia, found in nonhuman primates, can be transmitted to humans.

Trypanosoma cruzi is incorrectly identified as causing sleeping sickness.

Sentence should read: Trypanosoma brucei may infect nonhuman primates and humans, causing a disease called sleeping sickness, which is so named because of its effects on the nervous system.

Encephalitozoon cuniculi and Toxoplasma gondii are incorrectly categorized and discussed as flagellates.

Encephalitozoon cuniculi and Toxoplasma gondii should be categorized and discussed under Sporozoa. The last two paragraphs on page 87 under Flagellates should appear as the 2nd and 3rd paragraphs on page 88 under Sporozoa.

Moniliformis moniliformis is incorrectly listed as occurring in New World primates.

Prosthenorchis elegans should be listed as occurring in New World primates.

Inference is made that all fluke eggs have caps, or opercula, on one end.

Sentence should read: Some fluke eggs have caps, or opercula, on one end, and most contain an embryo.

Certain tapeworm species in an unnatural host are said to produce oocyte cysts.

Sentence should read: Occasionally certain tapeworm species infest an unnatural host and produce fluid-filled hydatid cysts in the host’s liver or other organs.

Onicola canis is misspelled.

Oncicola canis is the correct spelling.

Genus is incorrectly identified as Toxocara leonina.

Genus is incorrectly identified as Toxicara canis

Toxocara canis is the correct spelling.

The following table has been updated to clarify routes of administration of these two drugs:

Sentence reads: Figure 9.5 shows the use of ES cells from a 129 strain, agouti-colored mouse, injected into blastocysts from a C57BL strain, black-colored mouse.

Sentence should read: Figure 9.5 shows the use of ES cells from a 129 strain, white-colored mouse, injected into blastocysts from a C57BL/6 strain, black-colored mouse.

Sentence reads:...(containing the knockout gene) and ES cells from the C57BL strain...

Sentence should read:...(containing the knockout gene) and ES cells from the C57BL/6 strain...

Sentence reads: A chimera will have the coat color of both sets of parents, that is, part of its coat will be agouti and part will be black. Pups that did not incorporate the gene will be black, since they developed only from the inner cell mass of the C57BL donor blastocyst.

Sentence should read: A chimera will have patches of the coat color from each parent. In the case of a B6.129 chimera, the fur color produced by the 129 parent will be agouti, not white (although the 129 parent is a white-colored mouse), and the fur produced by the C57BL/6 parent will be black.

Sentence reads: Breeding a male chimera to a C57BL female should produce some agouti offspring if the male has incorporated the knock out gene in his sperm cells (Figure 9.6).

Sentence should read: Consider the case of a chimera of the chimera made from a C57BL/6 blastocyst that received ES cells from a 129 mouse (white coat). Figure 9.6 illustrates that when breeding a male chimera (B6.129) to a C57BL/6 female, agouti offspring in the litter proves that the male chimera incorporated the knockout gene in his sperm cells. In the same litter, the black offspring would be homogenous for the wild type (C57BL/6).

Sentence reads: bacteria that stain dark blue

Sentence should read: bacteria that stain dark blue to purple

Presently, Erysipelas is on the same line as Haemophilus suis. They need to be on different lines:

Bordatella bronchiseptica
Haemophilus suis
Pasteurella multocida
Erysipelas
Leptospirosis

Sentence reads: Gram positive organisms retain purple dye

Sentence should read: Gram positive organisms retain purple dye and appear dark blue to purple

Sentence reads: Results in the bacteria being colored red or blue

Sentence should read: results in the bacteria being colored red or dark blue to purple

A blue staining organism is said

This table has been updated. The corrected table is below.

Currently reads: This experiment involves the use of 10 animals per group and 15 groups (150 animals total).The process starts by placing the point of a pencil on the table of numbers without looking. This is the point of origin, and in this example the number is 10706 (the asterisk). The last three numbers (since there are three numbers in the number 150) in each set of numbers is the random number. Rows and columns can be read in any order, but in this case they were read from left to right and top to bottom. The random numbers, starting at the point of origin, read as 15, 91, 150, 130, 89, 105, 40, 114, 85 and 28

Should read: Suppose an experiment requires 99 animals divided in three equal groups (Groups A, B, and C). First, each animal is assigned a number (1-99). The table of random numbers can be used to randomize the assignment of animals to the different groups: Without looking, the point of a pencil is placed on the table of random numbers to determine the point of origin (10706 in this example, marked by an asterisk in the table). The table can be read in any order. For this example, we will read it from left to right and top to bottom.

Since the highest number assigned to our experimental animals is 99, a two-digit number, we will use only the last two digits of the random number (06 in this example).
Animal #6 will be assigned to group A.
Going from left to right, the next numbers are 46614 and 28357 so animals 14 and 57 would also be assigned to group A. This process will continue until 33 animals have been assigned to group A (animals 70, 52, 74 …). The animals corresponding to the next 33 random numbers would be assigned to Group B and the rest of the animals to group C.

If the end of the table is reached before all the animals are assigned, a new point of origin is selected as above and the process is repeated until all the animals have been assigned.